I’ve inherited a table that has thousands of records that require some trimming. Some entries have extra characters after the email domain “.com” or “.net”. It appears to be a pretty simple modification but it’s been along time for me. Can somone please point me to a post that handles such a script?
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Trim .com from string (Access 2003)
Home » Forums » AskWoody support » Productivity software by function » MS Access and database help » Trim .com from string (Access 2003)
- This topic has 7 replies, 4 voices, and was last updated 16 years, 6 months ago.
AuthorTopicWSjazman2k
AskWoody LoungerNovember 13, 2008 at 4:04 am #455269Viewing 0 reply threadsAuthorReplies-
WSHansV
AskWoody LoungerNovember 13, 2008 at 4:11 am #1132523 -
WSjazman2k
AskWoody Lounger -
WSjazman2k
AskWoody Lounger -
WSmbarron
AskWoody LoungerNovember 13, 2008 at 6:40 am #1132530Use this function as part of an update query. It will strip everything to the right of the first “.” it finds after the first “@” it finds. If there is no “@” or “.” after a “@” the original text is kept unchanged
Function StripIt(theAddress As String) As String Dim intAt As Integer intAt = InStr(theAddress, "@") If intAt = 0 Then StripIt = theAddress Exit Function End If If InStr(intAt, theAddress, ".") = 0 Then StripIt = theAddress Else StripIt = Left(theAddress, InStr(intAt, theAddress, ".") - 1) End If End Function
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WSJezza
AskWoody LoungerNovember 13, 2008 at 8:02 am #1132542Hi Dj
I have made a number of assumptions but we can manipulate the code for ant exceptions you may find.
The code “assumes” that there is only one type of email addess that ends in UK and seearches for the position of the last “.” in the email address, this iagain assumes that the extra characters that you are finding do not have that character in it. Have a look and see if there any problems ( there are bound to be a few)
Function strip(mail As String)
Dim intLength As IntegerIf Mid(mail, InStrRev(mail, “.”) + 1, 2) = “uk” Then
intLength = InStrRev(mail, “.”) + 2
strip = Left(mail, intLength)
Else
intLength = InStrRev(mail, “.”) + 3
strip = Left(mail, intLength)
End If
End Function
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WSjazman2k
AskWoody LoungerNovember 13, 2008 at 8:18 am #1132545Thanks for your help, All
I’ve done the quickest thing…which is place it in Excel
Insert the Stripit Function (Which was modified to a +3 on the right side of the trim)
Then called that from another column (= Stripit (a1))
This handled most of the nastinessThe ‘non-compliant’ ones were handled by filter and replace
Filter = Contains “.co.uk” {et al.}
Then I just copied and pasted and manually edited the dozen or so entries. No biggieInelegant…but it’s done!
Thanks again. -
WSJezza
AskWoody Lounger
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