• Grow Only Part

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    #353001

    I need to add a fixed amount to an amount that grows by 4% each year.

    For instance A1= 10,000 and A2 = 3,000

    The total in year 1 is 13,000 but in year 2 it is A1+ (A2*1.04). In year 3, its A1 + (A2*1.04*1.04)etc.

    Is there a function that would calculate this or do I just keep adding a *1.04 to each next year.

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    • #515020

      If, in column B, you put the date that you start counting then:

      =IF(TODAY()-B2<365,$A$1,$A$1+$A$2*(YEAR(TODAY())-YEAR(B2)-1))

      should do it.

      • #515024

        Thanks for the help but I think I wasn’t too clear on what I was trying to do. I’m not concerned with calculating time but rather incrementing the sum of 2 cells by 4% each year while also adding a base amount. The formulas I am using for year 1, 2, and 3 are below. I’m thinking there is a function I could use that would treat the amount that is growing (cells D10-11) like an annuity that earns interest (4%) AND would also let me add on the base amount (cell D9)

        =SUM($D$10:$D$11)*1.04+SUM($D$9)
        =SUM($D$10:$D$11)*1.04*1.04+SUM($D$9)
        =SUM($D$10:$D$11)*1.04*1.04*1.04+SUM($D$9)

        While my formula works, it seems rather unsophisticated.

        • #515029

          Actually, I wasn’t calculating the time. I was just finding how many year had elapsed from the time your process start and multiply that by your percentage increase. Do you try it?

        • #515033

          In cell B2 enter the percentage growth you are planning for, and enter the annual contribution you are going to make.
          Leave row 4 blank and enter the following formula in cell B5. Copy the formula aas many rows down as you like – you could also place meaningful labels in column A – like ‘growth,’ ‘contribution,’ and the year.

          =B4 * (1 + $B$2) + $B$3

          It will be easier to understand in a month if you name the cells B2 and B3, and ‘apply’ names to the formulas in B5:B?

        • #515149

          Sherry,

          One of Excel’s math operators is the exponentiation operator. Simply put, it raises a number to a power. Even more simply put, it multiplies a number by itself until you’ve done it the number of times given by the power.

          For example, 2 to the power of 3 is 2x2x2=8.

          In Excel, you’d write a formula as 2^3 (the symbol between the 2 and the 3 is shift on the 6 key). This operator has even higher precedence than multiply * and divide /.

          Now applying this to your problem:
          – $D$10:$D$11 are the sum of what you want raised to the power
          – $D$9 is the constant adder
          – put the percent growth in some cell, as suggested – call it $E$1

          Then I’d set up the following – I’ll use col A and B, starting in row 1, but you can use whatever you want;
          YEAR AMOUNT
          1 =(SUM($D$10:$D$11)*((1+$E$1)^A2)) + SUM($D$9)
          2 = [just drag the formula from B2]
          Note the only thing that changes in the above formula as you drag it is A2 changes to A3 to A4 to … Since A2 references the year, the year then becomes the “power” in the formula, which means you are multiplying the % up to the power given by the year.

          Hope this helps (and hope I didn’t screw up on the parens).

          Fred

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