Find a 10 digit number that has all the digits from 0 to 9 in it. The number is such that the first digit is divisible by 1. First 2 digits divisible by 2, first 3 by 3, first 4 by 4, so on and finally the ten digit number is divisible by 10.
Alan
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Nice one Rob. I also had to rattle my brain on those old rules of divisibility. Even then, it didn’t jump out and bite me – just reduced the amount of trial & error.
Alan
Edited – Extension –
Divisibility checks for 2,3,4,5,6,8,9 or 10 are fairly well known and easily derived.
But how do you check for divisibility by 7?
(Edited by tony55 on 06-Sep-04 18:18. )
I once knew the divisibility rules up to 13, just been thinking about them and those for 11 and 13 are escaping me at the moment (probably be able to find them easy enough by googling). As for divisibility by 7:
You take the last digit of the number and double it. Subtract this from the rest of the number. If the answer is divisible by 7 including cases where the answer is 0, then the number is divisible by 7
Added: Just googled and now I remember the answer for 11 and 13
(Edited by tony55 on 06-Sep-04 18:18. )
I once knew the divisibility rules up to 13, just been thinking about them and those for 11 and 13 are escaping me at the moment (probably be able to find them easy enough by googling). As for divisibility by 7:
You take the last digit of the number and double it. Subtract this from the rest of the number. If the answer is divisible by 7 including cases where the answer is 0, then the number is divisible by 7
Added: Just googled and now I remember the answer for 11 and 13
Nice one Rob. I also had to rattle my brain on those old rules of divisibility. Even then, it didn’t jump out and bite me – just reduced the amount of trial & error.
Alan
Edited – Extension –
Divisibility checks for 2,3,4,5,6,8,9 or 10 are fairly well known and easily derived.
But how do you check for divisibility by 7?
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