A bartender gets an ice cube weighing 20 grams from an ice bucket and puts it into an insulated cup containing 100 grams of water at 20 degrees Celsius. Will all the ice melt? What will be the final temperature of the water?
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Cool Drink
Home » Forums » Outside the box » Fun Stuff » Cool Drink
- This topic has 29 replies, 6 voices, and was last updated 18 years, 4 months ago.
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AskWoody LoungerDecember 4, 2006 at 11:38 am #1041634Just to be pedantic (and because I’m not clever/motivated enough to actually do the working out) – since no cup is 100 per cent insulated, the final temperature will (eventually) match the room temperature.
Or, presuming that someone drinks the water, perhaps it will be nearer body temperature…
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WSLeif
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WSsdckapr
AskWoody LoungerDecember 4, 2006 at 5:46 pm #1041689To be really pedantic, Waggers should have used “ambient temperature” instead of “room temperature”….
In actuality we could be very, very pedantic, and presume that the final temperature (given a long enough time frame) will be absolute zero when the universe has expanded to such and extent that there is actually no futher motion of any molecules…
I presumed (as did most people) that “final temperature” was the equilibrium temperature (the “immediate final temp”) of the warm water with the ice, not the “moderate-term final temp” of the ambient conditions or the “long-term final temp” of absolute zero.
I suppose that it could have a trick to get people to calcuate when either one of the 2 other answers was the “correct answer”, but either seems a little overly pedantic.
Steve
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WSAlanMiller
AskWoody LoungerDecember 6, 2006 at 12:37 am #1041965> presume that the final temperature (given a long enough time frame) will be absolute zero when the universe has expanded to such and extent that there is actually no futher motion of any molecules
But wouldn’t the problem itself then be irrevevant, since molecules themselves would have long ago dissociated into their more fundamental bits?
Alan
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WSAlanMiller
AskWoody LoungerDecember 6, 2006 at 12:21 pm #1042059Only the answer would have to be changed to indicate that water would not exist at “final” equilibrium. Then again, one could argue that the original constituents would still exist in some form, and be at absolute zero along with everything else. I think life would be rather boring at that stage of cosmological evolution.
Alan
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WSsdckapr
AskWoody LoungerDecember 6, 2006 at 12:38 pm #1042063It is still “water” even if we have given a separate name for the solid (ice) and gas (steam) phases. “Liguid” water may just be called “water”, but “ice” and “steam” can also be called “solid water” and “gaseous water”…
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I think life would be rather boring at that stage of cosmological evolution
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I think more “non-existent” than “boring”…
Steve
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WSAlanMiller
AskWoody LoungerDecember 6, 2006 at 2:08 pm #1042085But at such levels of cosmological expansion, everything would have been long since pulled apart. It’s not a local absolute zero – it’s a universal one, accompanying an expansion of everything within. The electrons originally orbiting the water’s oxygen nucleus might now be 3 suburbs away. You couldn’t still call that a water molecule, could you?
Alan
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WSsdckapr
AskWoody LoungerDecember 6, 2006 at 4:45 pm #1042126(Edited by sdckapr on 06-Dec-06 12:45. Added PS)
Yes, you are correct, if it is 3 suburbs away, definitely not water, but If it were only 2 suburbs away, then it could still be called water with very long “hydrogen bonding”…
Steve
PS this whole conversation reminds of the Short Story, The Last Question by Isaac Asimov -
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